-19k=-8k^2+15

Solution for -19k=-8k^2+15 equation:

-19k=-8k^2+15

We move all terms to the left:

-19k-(-8k^2+15)=0

We get rid of parentheses

8k^2-19k-15=0

a = 8; b = -19; c = -15;
Δ = b2-4ac
Δ = -192-4·8·(-15)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-29}{2*8}=\frac{-10}{16}
=-5/8
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+29}{2*8}=\frac{48}{16}
=3
$